Optimal. Leaf size=302 \[ -\frac{9\ 3^{3/4} \sqrt{2+\sqrt{3}} b^{5/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (A b-16 a B) \text{EllipticF}\left (\sin ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right ),-7-4 \sqrt{3}\right )}{320 a \sqrt{\frac{\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{\left (a+b x^3\right )^{3/2} (A b-16 a B)}{80 a x^5}+\frac{9 b \sqrt{a+b x^3} (A b-16 a B)}{320 a x^2}-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8} \]
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Rubi [A] time = 0.126118, antiderivative size = 302, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {453, 277, 218} \[ -\frac{9\ 3^{3/4} \sqrt{2+\sqrt{3}} b^{5/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (A b-16 a B) F\left (\sin ^{-1}\left (\frac{\sqrt [3]{b} x+\left (1-\sqrt{3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt{3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt{3}\right )}{320 a \sqrt{\frac{\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}+\frac{\left (a+b x^3\right )^{3/2} (A b-16 a B)}{80 a x^5}+\frac{9 b \sqrt{a+b x^3} (A b-16 a B)}{320 a x^2}-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8} \]
Antiderivative was successfully verified.
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Rule 453
Rule 277
Rule 218
Rubi steps
\begin{align*} \int \frac{\left (a+b x^3\right )^{3/2} \left (A+B x^3\right )}{x^9} \, dx &=-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8}-\frac{\left (\frac{A b}{2}-8 a B\right ) \int \frac{\left (a+b x^3\right )^{3/2}}{x^6} \, dx}{8 a}\\ &=\frac{(A b-16 a B) \left (a+b x^3\right )^{3/2}}{80 a x^5}-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8}-\frac{(9 b (A b-16 a B)) \int \frac{\sqrt{a+b x^3}}{x^3} \, dx}{160 a}\\ &=\frac{9 b (A b-16 a B) \sqrt{a+b x^3}}{320 a x^2}+\frac{(A b-16 a B) \left (a+b x^3\right )^{3/2}}{80 a x^5}-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8}-\frac{\left (27 b^2 (A b-16 a B)\right ) \int \frac{1}{\sqrt{a+b x^3}} \, dx}{640 a}\\ &=\frac{9 b (A b-16 a B) \sqrt{a+b x^3}}{320 a x^2}+\frac{(A b-16 a B) \left (a+b x^3\right )^{3/2}}{80 a x^5}-\frac{A \left (a+b x^3\right )^{5/2}}{8 a x^8}-\frac{9\ 3^{3/4} \sqrt{2+\sqrt{3}} b^{5/3} (A b-16 a B) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt{\frac{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} F\left (\sin ^{-1}\left (\frac{\left (1-\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt{3}\right )}{320 a \sqrt{\frac{\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt{3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt{a+b x^3}}\\ \end{align*}
Mathematica [C] time = 0.0784211, size = 82, normalized size = 0.27 \[ \frac{\sqrt{a+b x^3} \left (\frac{x^3 \left (\frac{A b}{2}-8 a B\right ) \, _2F_1\left (-\frac{5}{3},-\frac{3}{2};-\frac{2}{3};-\frac{b x^3}{a}\right )}{\sqrt{\frac{b x^3}{a}+1}}-\frac{5 A \left (a+b x^3\right )^2}{a}\right )}{40 x^8} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.024, size = 653, normalized size = 2.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{3}{2}}}{x^{9}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B b x^{6} +{\left (B a + A b\right )} x^{3} + A a\right )} \sqrt{b x^{3} + a}}{x^{9}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.50204, size = 196, normalized size = 0.65 \begin{align*} \frac{A a^{\frac{3}{2}} \Gamma \left (- \frac{8}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{8}{3}, - \frac{1}{2} \\ - \frac{5}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{8} \Gamma \left (- \frac{5}{3}\right )} + \frac{A \sqrt{a} b \Gamma \left (- \frac{5}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{5}{3}, - \frac{1}{2} \\ - \frac{2}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{5} \Gamma \left (- \frac{2}{3}\right )} + \frac{B a^{\frac{3}{2}} \Gamma \left (- \frac{5}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{5}{3}, - \frac{1}{2} \\ - \frac{2}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{5} \Gamma \left (- \frac{2}{3}\right )} + \frac{B \sqrt{a} b \Gamma \left (- \frac{2}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, - \frac{1}{2} \\ \frac{1}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{2} \Gamma \left (\frac{1}{3}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{3} + A\right )}{\left (b x^{3} + a\right )}^{\frac{3}{2}}}{x^{9}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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